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18x^2+33x+9=0
a = 18; b = 33; c = +9;
Δ = b2-4ac
Δ = 332-4·18·9
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-21}{2*18}=\frac{-54}{36} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+21}{2*18}=\frac{-12}{36} =-1/3 $
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